Caranya ya sekalian yg detail, terima kasih
79. ( g o f )(x) = g [ f(x) ]
4x + 1 = g( 2x - 3 )
Misal : 2x - 3 = R
2x = R + 3
[tex]x = \frac{r + 3}{2} \\ 4( \frac{r + 3}{2} ) + 1 = g(r)[/tex]
2( R + 3 ) + 1 = g(R)
2R + 6 + 1 = g(R)
2R + 7 = g(R)
g(x) = 2x + 7
g(x) = y
2x + 7 = y
2x = y - 7
[tex]x = \frac{y - 7}{2} \\ g {}^{ - 1} (x) = \frac{x - 7}{2} \\ g {}^{ - 1} (3) = \frac{3 - 7}{2} \\ = \frac{ - 4}{2} = - 2(e.)[/tex]
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